| Personal data | |
|---|---|
| Surname | Tuluevsky |
| Name | Mark |
| Patronym | Abramovich |
| Birth year | 1896 |
| Birth month | 3 |
| Birth day | 3 |
| Birth place | Klimovichi |
| Sex | M |
Tuluevsky Mark Abramovich (3 March 1896, Klimovichi, Mogilev Province — ?) — physician.
Mark Tuluevsky studied at a gymnasium in Klimovichi, graduating in 1927. In 1916, he entered the Faculty of Law at Kharkiv University, transferring in 1917 to the Faculty of Medicine. In 1918–1919, he served as a volunteer in the Red Army, working on military санитар trains. In 1924, he graduated from the medical faculty and in 1925 completed his clinical internship.
Until 1931, he worked as head of district health departments (Raizdrav) in various cities in the Donbas and Kharkiv regions.
During the Second World War, he was evacuated to Barnaul (Altai Territory), where from 1941 to 1945 he served as head of the medical department of the city health administration. On 26 July 1945, he was transferred to Riga and appointed head of the health department of the Proletarian District. In 1950, he was reassigned to the ambulance service; in the summer of that year, he also served as chief physician of the resort polyclinic “Rīgas Jūrmala.” From 30 June 1950, he was chief physician of Polyclinic No. 5 of the Kirov District of Riga.
He was awarded an honorary certificate, the medal “For Valiant Labour in the Great Patriotic War,” and the Order of the Badge of Honour.
His father was Abram Moiseevich Tuluevsky (d. 1934), and his mother Raissa Markovna Tuluevskaya (d. 1929).
He was married to Olga Isakovna Tuluevskaya, a physician-radiologist. Their son was Valentin Tuluevsky.